- A$Fe (III)$
- B$Mn (II)$
- C$Cr (I)$
- ✓$P (0)$
All other elements are $d-block$ elements therefore has valance electron in $3 d$ subshell.
Electronic configuration of $Cr ( I )$ is $1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 3 d^5$.
Electronic configuration of $F (III)$ is $1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 3 d^5$
Electronic configuration of $Mn (II)$ is $1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 3 d^5$.
So, all these have valence electrons in $3 d$ - subshell.
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Given, $\lambda_{\left(\mathrm{Ag}^{+}\right)}^{\circ}=6 \times 10^{-3} \mathrm{Sm}^2 \mathrm{~mol}^{-1}, \lambda_{\left(\mathrm{Br}^{-}\right)}^{\circ}=8 \times 10^{-3} \mathrm{Sm}^2 \mathrm{~mol}^{-1}, \lambda_{\left(\mathrm{NO}_{\mathrm{j}}\right)}^{\circ}=7 \times 10^{-3} \mathrm{Sm}^2 \mathrm{~mol}^{-1}$.
Arginine, Phenylalanine, Aspartic acid, Cysteine, Histidine, Valine, Proline