Download App

4. Chemical bonding and molecular structure — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry4. Chemical bonding and molecular structure1 Mark
MCQ
Bond polarity of diatomic molecule is because of
  • A
    Difference in electron affinities of the two atoms
  • ✓
    Difference in electronegativities of the two atoms
  • C
    Difference in ionisation potential
  • D
    All of these
✓

Answer

Correct option: B.
Difference in electronegativities of the two atoms
(b) Polarity character is due to the difference in electronegativity of two atoms or molecule.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 4. Chemical bonding and molecular structure→4. Chemical bonding and molecular structure — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

What concentration of $Ac^-$ ions will reduce $H_3O^+$ ion to $2 × 10^{-4}\ M$ in $0.40\ M$ solution of $HAc$ ? $K_a (HAc) = 1.8 × 10^{-5}$ ?
→
Among the following compounds, which one has the shortest $C - Cl$ bond $?$
→
The molecule having one unpaired electron is
→
Five valence electrons of $P^{15}$ are labelled as $\mathop {\boxed{AB}}\limits_{3s} \,\mathop {\boxed{X|Y|Z}}\limits_{3p} $ If the spin quantum numbers of $B$ and $Z$ is $ + \frac{1}{2}$ , the group of electron with three of the quantum number $(n, l, m)$ same are
→
The dehydrohalogenation of neopentyl bromide with alcoholic $KOH$ mainly gives
→
In a Lassaignes’s test for sulphur in the organic compound with sodium nitroprusside solution the purple colour formed is due to
→
Electronic configuration of deuterium atom is
→
In the redox reaction

$x\ MnO + y\ PbO_2 + z\ HNO_3 \to a\ HMnO_4 + b\ Pb(NO_3 )_2 + c\ H_2O$

→
Three elements $X , Y$ and $Z$ are in the $3^{ rd }$ period of the periodic table. The oxides of $X$, $Y$ and $Z ,$ respectively, are basic, amphoteric and acidic. The correct order of the atomic numbers of $X , Y$ and $Z$ is 
→
The correct order of hybridization of the central atom in the following species $N{H_3}$, ${[PtC{l_4}]^{2 - }},\,PC{l_5}$ and $BC{l_3}$ is
→