MCQ
Carbolic acid is
- A${C_6}{H_5}CHO$
- B${C_6}{H_6}$
- C${C_6}{H_5}COOH$
- ✓${C_6}{H_5}OH$
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(At. nos. $Cr = 24, Mn = 25, Fe = 26, Co = 27$)
$(I)$ $BO_3^{-3} > CO_3^{-2} > NO_3^-$
$(II)$ $ClO_4^-> SO_4^{-2} > PO_4^{-3}$
$(III)$ $BF_3 > BCl_3 > BBr_3$
$(IV)$ $AlCl_3 > BCl_3$
In the above reaction, $3.9\, g$ of benzene on nitration gives $4.92\, g$ of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is............. $\%$. (Round off to the Nearest Integer).
(Given atomic mass: $C : 12.0\, u , H : 1.0\, u$$O : 16.0\, u , N : 14.0\, u )$