MCQ
Carbon suboxide ${C_3}{O_2}$ has
- ✓Linear structure
- BBent structure
- CTrigonal planar structure
- DDistorted tetrahedral structure
$O = C = C = C = O \leftrightarrow {O^ - } - C \equiv C - C \equiv {O^ + }$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Statement $(I)$ : The oxidation state of an element in a particular compound is the charge acquired by its atom on the basis of electron gain enthalpy consideration from other atoms in the molecule.
Statement $(II)$ : $\mathrm{p} \pi-\mathrm{p} \pi$ bond formation is more prevalent in second period elements over other periods.
In the light of the above statements, choose the most appropriate answer from the options given below :
$4NH_3 + 5O_2 \to 4NO + 6H_2O$
$\begin{array}{*{20}{c}}
{\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH = C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow[{2.\,KOH - EtOH,\,heat}]{{1.\,HBr}}$
The major end product formed is :-