MCQ
Carbylamine test is done by heating alcoholic $KOH$ with
- AChloroform and silver powder
- ✓Trihalogen methane and primary amine
- CAlkyl halide and primary amine
- DAlkyl cyanide and primary amine
$CHC{l_3} + C{H_3}N{H_2} + \mathop {3KOH}\limits_{{\rm{alc}}{\rm{.}}} \to \mathop {C{H_3}N\vec = }\limits_{\scriptstyle{\rm{Methyl }}\atop\scriptstyle{\rm{isocyanide}}} \mathop {C + 3KCl + 3{H_2}O}\limits_{} $
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$C{H_3}C{H_2}OH\xrightarrow{{P + {I_2}}}A\xrightarrow[{ether}]{{Mg}} $ $B\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D$
Temperature $\quad$ Equilibrium constant
$\begin{array}{ll} T _{1}=25^{\circ} C & K _{1}=100 \\ T _{2}=100^{\circ} C & K _{2}=100\end{array}$
The values of $\Delta H ^{\circ}, \Delta G ^{\circ}$ at $T _{1}$ and $\Delta G ^{\circ}$ at $T _{2}$ (in $kJ\, mol ^{-1}$ ) respectively, are close to $\left[\right.$ Use $\left. R =8.314\, JK ^{-1} mol ^{-1}\right]$
$C{H_3}C{H_2}C{H_2}Br$ $\xrightarrow{{KOH(alc.)}}\,(A)\,\xrightarrow{{HBr}}(B)\,$ $\xrightarrow{{KOH(aq.)}}(C)$ The product $(C)$ is