- ✓Stephen's reduction
- BCannizzaro reaction
- CClemmensen's reduction
- DRosenmund's reduction
$R - C \equiv N +2 H \stackrel{ SnCl _2 / HCl }{\longrightarrow} \underset{\text { alidine }}{ RCH }=\underset{\text { hydrochloride }}{ NH \cdot HCl } \stackrel{ H _2 O }{\longrightarrow} \underset{\text { aldehyde }}{ RCHO }+ NH _4 Cl$
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$CH_3-CH_2-OH$ $\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)$ $\xrightarrow{{B{r_2}/KOH}}(C)$
$(C)$ will be :
The two products formed in above reaction are -
Statement $I :$ In $CuSO _{4} .5 H _{2} O , Cu - O$ bonds are present.
Statement $II :$ In $CuSO _{4} .5 H _{2} O$, ligands coordinating with $Cu$ $(II)$ ion are $O$-and $S$-based ligands.
In the light of the above statements, choose the correct answer from the options given below