MCQ
$Ce-58 $ is a member of
- A$s-$ block
- B$p-$ block
- C$d-$ block
- ✓$f-$ block
Since, its last electron enter in $f- $ sub-shell, therefore it is a member of $f-$ block.
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$\mathrm{A}_{2}(\mathrm{g})+\mathrm{B}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{X}_{2}(\mathrm{g}) \Delta_{r} \mathrm{H}=-\mathrm{X} \mathrm{kJ} ?$