MCQ
Choose the correct answer from the given four options. The feasible solution for a LPP is shown in. Let Z = 3x - 4y be the objective function.

- A(5, 0)
- B(6, 5)
- C(6, 8)
- D(4, 10)

Solution:
| Corner points | Corresponding value of Z = 3x - 4y |
| (0, 0) (5, 0) (6, 5) (6, 8) (4, 10) (0, 8) | 0 15 (Maxmimum) -2 -14 -28 -32 |
Hence, maximum of Z occurs at (5, 0) and its maximum value is 27.
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$\text{A}=\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix},$ if n is an even natural number
$\text{A}=\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix},$ if n is an odd natural number
$\text{A}=\begin{bmatrix} -1 & 0 \\ 0 & 1 \end{bmatrix},\text{if n}\in\text{N}$
($A$) $\quad \alpha=0, k=8$
($B$) $4 \alpha-k+8=0$
($C$) $\operatorname{det}(P \operatorname{adj}(Q))=2^9$
($D$) $\operatorname{det}(Q \operatorname{adj}(P))=2^{13}$