MCQ
Choose the correct relation between $l_1$ and $l_2$ ?
- A$l_1 = l_2$
- B$l_1 > l_2$
- ✓$l_1 < l_2$
- D$l_2 = 2l_1$
✓
Answer
Correct option: C.
$l_1 < l_2$
c
$(c)$ Terminal hydrogens are in same plarie $\therefore$ $l_2 > l_1$
$(c)$ Terminal hydrogens are in same plarie $\therefore$ $l_2 > l_1$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Born-Haber cycle is used to determine
One mole of $S{O_3}$ was placed in a litre reaction vessel at a certain temperature. The following equilibrium was established $2S{O_3}$ $ \rightleftharpoons $ $2S{O_2} + {O_2}$ At equilibrium $0.6$ moles of $S{O_2}$ were formed. The equilibrium constant of the reaction will be
→In $Xe{F_4}$ hybridization is
→In which of the following reaction $H_2O_2$ acts as reducing agent
$(I)$ $H_2O_2 + 2H^+ + 2e^-\to 2H_2O$
$(II)$ $H_2O_2 + 2e^-\to O_2 + 2H^+$
$(III)$ $H_2O_2 + 2e^-\to 2 OH^-$
$(IV)$ $H_2O_2 + 2OH^-+ 2e^-\to O_2 + 2H_2O$
→$(I)$ $H_2O_2 + 2H^+ + 2e^-\to 2H_2O$
$(II)$ $H_2O_2 + 2e^-\to O_2 + 2H^+$
$(III)$ $H_2O_2 + 2e^-\to 2 OH^-$
$(IV)$ $H_2O_2 + 2OH^-+ 2e^-\to O_2 + 2H_2O$
Atoms in a ${P_4}$ molecule of white phosphorus are arranged regularly in space in which of the following way
→What is the major product $"P"$ of the following reaction?
→A solution of weak acids is diluted by adding an equal volume of water. Which of the following will not change
Molality (m) of $3 \mathrm{M}$ aqueous solution of $\mathrm{NaCl}$ is:
→(Given : Density of solution $=1.25 \mathrm{~g} \mathrm{~mL}^{-1}$, Molar mass in $\left.\mathrm{g} \mathrm{mol}^{-1}: \mathrm{Na}-23, \mathrm{Cl}-35.5\right)$
At equilibrium on increasing pressurre boiling point of $H_2O$
→The compound which is not isomeric with diethyl ether is