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$3\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{B} \xrightarrow{{4\,HCl}}\mathop {2C}\limits_{(Purple)} + Mn{O_2} + 2{H_2}O$
$3\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} \xrightarrow{{{H_2}O,KI}}2\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{A} + 2KOH + \underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{D} $
In the above sequence of reactions, $\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{A}$ and $\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{D} $ , respectively are
Assertion $A$ : $Image-I$ can be easily reduced using $Zn - Hg / HCl$ to $Image-II$
Reason $R : Zn - Hg / HCl$ is used to reduce carbonyl group to $- CH _2-$ group.
In the light of the above statements, choose the correct answer from the options given below:
