MCQ
Column $- I$ gives certain physical terms associated with flow of current through a metallic conductor. Column $- II$ gives some mathematical relations involving electrical quantities. Match Column $- I$ and Column $- II$ with appropriate relations.
Column $- I$ Column $- II$
$(A)$ Drift Velocity $(P)$ $\frac{m}{n e^{2} \rho}$
$(B)$ Electrical Resistivity $(Q)$ $\mathrm{ne} v_{\mathrm{d}}$
$(C)$ Relaxation Period $(R)$ $\frac{\mathrm{eE}}{\mathrm{m}} \tau$
$(D)$ Current Density $(S)$ $\frac{E}{J}$
  • $(A)- (\mathrm{R}),(\mathrm{B})-(\mathrm{S}),(\mathrm{C})-(\mathrm{P}),(\mathrm{D})-(\mathrm{Q})$
  • B
    $(A)-(R), (B)-(S), (C)-(Q), (D)-(P)$
  • C
    $(A)-(R), (B)-(P), (C)-(S), (D)-(Q)$
  • D
    $(A)-(R), (B)-(Q), (C)-(S), (D)-(P)$

Answer

Correct option: A.
$(A)- (\mathrm{R}),(\mathrm{B})-(\mathrm{S}),(\mathrm{C})-(\mathrm{P}),(\mathrm{D})-(\mathrm{Q})$
a
$J=\frac{I}{A}=n e v_{d}=\frac{n e^{2} \tau}{m} E=\sigma E=\frac{E}{\rho}$

$V_{d}=\frac{e E}{m} I ; \rho=\frac{m}{n e^{2} \tau}$ or $\rho=\frac{E}{J}, J=n e v_{d}$

$A \rightarrow R \quad B \rightarrow S \quad D \rightarrow Q$

$\tau=\frac{m}{n e^{2} \rho}$

$C \rightarrow P$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A positively charged thin metal ring of radius $R$ is fixed in the $xy - $ plane with its centre at the $O$. A negatively charged particle $P$ is released from rest at the point $(0,\,0,\,{z_0})$, where ${z_0} > 0$. Then the motion of $P$ is
If in a nuclear fusion process the masses of the fusing nuclei be $\mathrm{m}_1$ and $\mathrm{m}_2$ and the mass of the resultant nucleus be $\mathrm{m}_3$, then
The energy gap in a conductor at room temperature is $.........$ .
The radius of curvature of the curved surface of a plano$-$convex lens is $20 \ cm.$ If the refractive index of the material of the lens be $1.5,$ it will
$A$ turnip sits before a thin converging lens, outside the focal point of the lens. The lens is filled with a transparent gel so that it is flexible; by squeezing its ends toward its center [as indicated in figure $(a)$], you can change the curvature of its front and rear sides. The lateral height of image.
Resistance of semiconductor at $0^\circ K$ is
A wave pulse, travelling on a two -piece string, gets partially reflected and partially transmitted at the junction. The reflected wave is inverted in shape as compared to the incident one. If the incident wave has wavelengt $\lambda$ and the transmitted wave $\lambda'.$
A boy stands straight infront of a mirror at a distance of 30 cm away from it. He sees his erect image whose height is $\frac {1}{5}$th of his real height. The mirror he is using is
A conducting sphere of radius 10cm is charged 10μC. Another uncharged sphere of radius 20 cm is allowed to touch it for some time. After that if the sphere are separated, then surface density of charges, on the spheres will be in the ratio of
Assertion : The focal length of the mirror is f and distance of the object from the focus is u, the magnification of the mirror is f / u.
Reason : Magnification $=\frac{\text { Size of image }}{\text { Size of object }}$