MCQ
Complete the reaction: ${ }_{86} \mathrm{Rn}^{220} \rightarrow{ }_{84} \mathrm{Po}^{216}+ ......$
- A$\beta$
- B$\gamma$
- ✓$\alpha$
- D$\text{H}^1_1$
✓
Answer
Correct option: C.
$\alpha$
${ }_{86} \mathrm{Rn}^{220} \rightarrow{ }_{84} \mathrm{Po}^{216}+z \mathrm{X}^A$
$Z + 84 = 86$ and $220 = 216 + A$
So, $Z = 2$ and $A = 4$
$2\alpha^4$
So, it is $\alpha$ particle.
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