MCQ
Complex $[Co(NH_3)5Br]SO_4$ and $[Co(NH_3)_5SO_4]Br$ can be identified by
- A$BaCl_2$
- B$AgNO_3$
- C$PbCl_2$
- ✓All of these
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$(I)\, [Co(NO_2)_3(NH_3)_3]$
$(II)$ cis $-[ RhCl_2 (NH_3)_4]^+$
$(III)\, [Cr(OX)_3]^{-3}$
$(IV)$ cis $ -[PtCl_2 (en)]$
$(V)$ trans $-[Cr(en)_2 Br_2]^+$
$(VI)$ cis $-[Cr(en)_2 Br_2]^+$
$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}\mathop {\xrightarrow{{Conc.{H_2}S{O_4}}}}\limits_{Distillation} [X]$
$[X]$ will be :
The Gibbs free energy change for the above reaction at $298\, K$ is $x \times 10^{-1} \,k\,J\, mol ^{-1}$;
The value of $x$ is ..... [nearest integer]$\left [\text { Given : } E _{ Cu ^{2} / / Cu }=0.34\, V ; E _{ Sn ^{2} / Sn }^{\ominus}=-0.14 \,V ; F=96500\, C\, mol ^{-1}\right]$
