MCQ
Consider the above chemical reaction. Product " $\mathrm{A}$ " is:
- A
- ✓
- C
- D
✓
Answer
Correct option: B.
b
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In the following reaction $X$ is
→$C{H_3}N{H_2} + X + KOH \to C{H_3}NC$ (highly offensive odour)
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{\mathop {C{H_3}MgBr}\limits_{(excess)} + Et - O - C - O - Et\xrightarrow[{(2){H^ \oplus }}]{}(A)}
\end{array}$ ; Product $A$ is
→{\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{\mathop {C{H_3}MgBr}\limits_{(excess)} + Et - O - C - O - Et\xrightarrow[{(2){H^ \oplus }}]{}(A)}
\end{array}$ ; Product $A$ is
Match List$-I$ with List$-II :$
→|
List$-I$ (Chemical Reaction) |
List$-II$ (Reagent used) |
| $(a)$ $\mathrm{CH}_{3} \mathrm{COOCH}_{2} \mathrm{CH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ |
$(i)$ $\mathrm{CH}_{3} \mathrm{MgBr} / \mathrm{H}_{3} \mathrm{O}^{+}$ $(1 .$ equivalent $)$ |
| $(b)$ $\mathrm{CH}_{3} \mathrm{COOCH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{CHO}$ | $(ii)$ $\mathrm{H}_{2} \mathrm{SO}_{4} / \mathrm{H}_{2} \mathrm{O}$ |
| $(c)$ $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{N} \rightarrow \mathrm{CH}_{3} \mathrm{CHO}$ | $(iii)$ $\mathrm{DIBAL}-\mathrm{H} / \mathrm{H}_{2} \mathrm{O}$ |
| $(d)$ $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{N} \rightarrow \mathrm{CH}_{3}CO\mathrm{CH}_{3}$ | $(iv)$ $\mathrm{SnCl}_{2}, \mathrm{HCl} / \mathrm{H}_{2} \mathrm{O}$ |
Choose the most appropriate match :
The half life of a first order reaction is
$S_{N_1}$ reaction on optically active substrates mainly gives:
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Which of the following will give $Fe^{3+}$ ions in the solution?
→The correct order of $N-$compounds in its decreasing order of oxidation states is
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$\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C-H\xrightarrow{H{{O}^{-}}/\Delta }\underset{(73\%)}{\mathop{(A)}}\,; \\
\end{matrix}$ Product $(A)$ is
→O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C-H\xrightarrow{H{{O}^{-}}/\Delta }\underset{(73\%)}{\mathop{(A)}}\,; \\
\end{matrix}$ Product $(A)$ is