Athe current in the $5\, \Omega$ resistor is $2\, A$
Bthe current in the $5\, \Omega$ resistor is $1\, A$
Cthe potential difference $V_A - V_B$ is $10\, V$
Dthe potential difference $V_A- V_B$ is $5\, V$
Medium
Download our app for free and get started
Athe current in the $5\, \Omega$ resistor is $2\, A$
a $R_{e q}=14 \Omega$
$I=\frac{28}{14}=2 A m p$
$V_{A}+3 \times 1-10 \times 1=V_{B}$
$V_{A}-V_{B}=7$ volt
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
First, a set of ${n}$ equal resistors of $10\; \Omega$ each are connected in series to a battery of emf $20\; {V}$ and internal resistance $10\; \Omega .$ A current $I$ is observed to flow. Then, the $n$ resistors are connected in parallel to the same battery. It is observed that the current is increased $20$ times, then the value of $n$ is .... .
The series combination of two batteries, both of the same emf $10 \mathrm{\;V},$ but different internal resistance of $20\; \Omega$ and $5\; \Omega,$ is connected to the parallel combination of two resistors $30\; \Omega$ and $\mathrm{R}\; \Omega .$ The voltage difference across the battery of internal resistance $20\; \Omega$ is zero, the value of $\mathrm{R}(\text { in } \Omega)$ is
A $200\,\Omega $ resistor has a certain color code. If one replaces the red color by green in the code, the new resistance will be .............. $\Omega$
The charge flowing in a conductor changes with time as $Q ( t )=\alpha t -\beta t ^2+\gamma t ^3$. Where $\alpha, \beta$ and $\gamma$ are constants. Minimum value of current is :
The figure shows a circuit diagram of a ‘Wheatstone Bridge’ to measure the resistance $G$ of the galvanometer. The relation $\frac{P}{Q} = \frac{R}{G}$ will be satisfied only when