The series combination of two batteries, both of the same emf $10 \mathrm{\;V},$ but different internal resistance of $20\; \Omega$ and $5\; \Omega,$ is connected to the parallel combination of two resistors $30\; \Omega$ and $\mathrm{R}\; \Omega .$ The voltage difference across the battery of internal resistance $20\; \Omega$ is zero, the value of $\mathrm{R}(\text { in } \Omega)$ is 
JEE MAIN 2020, Diffcult
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$\mathrm{E}_{1} =\mathrm{E}-\mathrm{ir}$ $=10-\mathrm{i} \times20=0$

$\mathrm{i}=0.5 \mathrm{A}$

$\mathrm{E}_{2}=\mathrm{E}-\mathrm{ir}$

$=10-0.5 \times 5$ $=7.5 \mathrm{V}$

$\mathrm{E}_{\mathrm{net}}=\mathrm{E}_{1}+\mathrm{E}_{2}=7.5 \mathrm{V}$

$\mathrm{i}=\mathrm{i}_{1}+\mathrm{i}_{2}$

$0.5=\frac{7.5}{x}+\frac{7.5}{30}$

$\mathrm{x}=30 \Omega$

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