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MODEL PAPER 3 (BASIC) — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsMODEL PAPER 3 (BASIC)1 Mark
MCQ
Consider the following frequency distribution:
Class0-56-1112-1718-2324-29
Frequency131015811
The upper limit of the median class is
  • A
    18.5
  • ✓
    17.5
  • C
    18
  • D
    17
✓

Answer

Correct option: B.
17.5
(B) 17.5
Explanation: Given, classes are not continuous, so we make continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class.
ClassFrequencyCumulative frequency
-0.5-5.51313
5.5-11.51023
11.5-17.51538
17.5-23.5846
23.5-29.51157
Here, $\frac{N}{2}=\frac{57}{2}=28.5$, which lies in the interval 11.5 - 17.5.
Hence, the upper limit is 17.5 .

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