Question
Consider the objective function Z = 40x + 50y The minimum number of constraints that are required to maximize Z are:
- 4
- 2
- 3
- 1
✓
Answer
- 3
Since in the given function Z = 40x + 50y, two variables are used.
So, the two constraints will be $\text{x}\geq0,\text{y}\geq0$ and the third one will be of the type
$\text{ax}+\text{by}\geq\text{c}.$
Hence, at least 3 constraints are required.
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