Question
Construct a quadrilateral $ABCD$, such that $AB = BC = CD = 4.4 \ cm, \angle B = 90^\circ$ and $\angle C = 120^\circ .$

Answer

The rough figure is as follow

The Actual figure is constructed as follow:

Steps :
  1. Draw $BC = 4.4 \ cm.$
  2. At $B$, draw $\angle PBC = 90^\circ$ .
  3. Cut $BA = 4.4 \ cm.$
  4. At $C$, draw $\angle QCB = 120^\circ .$
  5. Cut $CD = 4.4 \ cm.$
  6. Join $AD.$
    Thus $ABCD$ is the required quadrilateral.

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