Question
Construct a quadrilateral PQRS, in which PQ = 4cm, QR = 5cm, $\angle\text{P}=50^\circ,\angle\text{P}=110^\circ$ and $\angle\text{R}=70^\circ.$
✓
Answer
Steps of construction:Step I: Draw PQ = 4cm.
Step II: Construct $\angle\text{XPQ}=50^\circ$ at P and $\angle\text{PQY}=110^\circ$ at Q.
Step III: With Q as the centre and radius 5cm, cut off QR = 5cm.
Step IV: At R, draw $\angle\text{QRZ}=70^\circ$ such that it meets PX at S.
The quadrilateral so obtained is the required quadrilateral.
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