MCQ
Correct configuration of $F{e^{ + 3}}$ $[26] $ is
- ✓$1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^5}$
- B$1{s^2},2{s^2}s{p^6},3{s^2}3{p^6}3{d^3},4{s^2}$
- C$1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^6},4{s^2}$
- D$1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^5},4{s^1}$
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$\begin{array}{*{20}{c}} {C{H_2}OH} \\ {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {C{H_2}OH} \end{array}$ $+$ oxalic acid $\xrightarrow{{{{210}^o}C}}$ $\quad\quad X$
$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad$(major product)
$(a)$ saline hydrides produce $H_2$ gas when reacted with $H_2O.$
$(b)$ reaction of $LiAH_4$ with $BF_3$ leads to $B_2H_6.$
$(c)$ $PH_3$ and $CH_4$ are electron - rich and electron-precise hydrides, respectively.
$(d)$ $HF$ and $CH_4$ are called as molecular hydrides.
The missing product $(s)$ is $(are)$