MCQ
Correct electron affinity order is
- A$O < N < Cl < S$
- ✓$N < O < S < Cl$
- C$Cl > O > S > N$
- D$N = Cl > O = S$
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| Energy level | $K$ | $L$ | $M$ | $N$ |
| $n=1$ | $n=2$ | $n=3$ | $n=4.....n=\infty$ | |
| Energy | $- 864 \,a.u.$ | Zero |
the excitation energy needed to raise the electron from $M$ level to $n = \infty$ would be :
$(I)\,\,C{H_2} = CH - \mathop C\limits^ \oplus {H_2}$
$(II)\,\,C{H_3} - CH_2 - \mathop C\limits^ \oplus {H_2}$


$A \xrightarrow[ { Cu\; tube }]{\text { Redhot }}\mathrm{B} \xrightarrow[ Anhydrous AlCl_3]{\mathrm{CH}_{3} \mathrm{Cl}(1 \mathrm{eq}} \mathrm{C}$
($A$ is a lowest molecular weight alkyne)