MCQ
Correct order for reaction with alcoholic $KOH$


- ✓$a > c > b > d $
- B$a > b > c > d$
- C$d > b > c > a$
- D$a > d > b > c$

$3^{\circ}>2^{\circ}>1^{\circ}$
The order of leaving group in $E 2$ elimination reaction is shown below :
$R - I > R - Br > R - Cl$
Therefore, the correct order for reaction with alcoholic $KOH$ is as follows :
$a > c > b > d$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List $-I$ | List $-II$ |
| $A$ $XeF_4$ | $1.$ Pyramidal |
| $B$ $XeF_6$ | $2.$ $T-$ shape |
| $C$ $XeO_3$ | $3.$ Distorted octahedral |
| $D$ $XeOF_2$ | $4.$ Square planar |


(Given : Molar mass of $\mathrm{NaOH}$ is $40 \mathrm{~g} / \mathrm{mol}$ )