Question
$\cos^{-1}[\cos(2\cot^{-1}(\sqrt2-1))]=$ ______.
- $\sqrt2-1$
- $1+\sqrt2$
- $\frac{\pi}{4}$
- $\frac{3\pi}{4}$
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$\frac{\pi}{2}$
$\frac{\pi}{3}$
$\frac{\pi}{4}$
$\frac{5\pi}{12}$
Consider a matrix $A=\left[a_{i j}\right]_{3 \times 3}$ where
$a_{i j}=J_{6+i, 3}-J_{i+3,3}, \quad i \leq j$
$\quad\quad\quad\quad\quad\quad0 , \quad\quad\quad i>j$.
Then $\left|\operatorname{adj} A^{-1}\right|$ is :