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STD 12 - 2. inverse trigonometric function — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 2. inverse trigonometric function1 Mark
MCQ
${\cos ^{ - 1}}\left( {\frac{{15}}{{17}}} \right) + 2{\tan ^{ - 1}}\left( {\frac{1}{5}} \right) = $
  • A
    $\frac{\pi }{2}$
  • B
    ${\cos ^{ - 1}}\left( {\frac{{171}}{{221}}} \right)$
  • C
    $\frac{\pi }{4}$
  • ✓
    None of these
✓

Answer

Correct option: D.
None of these
d
(d) ${\cos ^{ - 1}}\left( {\frac{{15}}{{17}}} \right) + 2{\tan ^{ - 1}}\left( {\frac{1}{5}} \right)$

$ = {\cos ^{ - 1}}\left( {\frac{{15}}{{17}}} \right) + {\cos ^{ - 1}}\left( {\frac{{1 - 1/25}}{{1 + 1/25}}} \right)$

$ = {\cos ^{ - 1}}\left( {\frac{{15}}{{17}}} \right) + {\cos ^{ - 1}}\left( {\frac{{12}}{{13}}} \right)$

$ = {\cos ^{ - 1}}\left( {\frac{{15}}{{17}} \times \frac{{12}}{{13}} - \sqrt {1 - {{\left( {\frac{{15}}{{17}}} \right)}^2}} \sqrt {1 - {{\left( {\frac{{12}}{{13}}} \right)}^2}} } \right)$

$ = {\cos ^{ - 1}}\left( {\frac{{140}}{{221}}} \right)$.

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