MCQ
$\cot (45^\circ + \theta )\cot (45^\circ - \theta ) = $
- A$-1$
- B$0$
- ✓$1$
- D$\infty $
$= \tan (90^\circ - 45^\circ - \theta )\cot (45^\circ - \theta )$
$ = \tan (45^\circ - \theta )\cot (45^\circ - \theta ) = 1$.
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| ઉંમર | $15$ | $16$ | $17$ | $18$ | $19$ | $20$ |
| વિધાથીઓ ની સંખ્યા | $5$ | $8$ | $5$ | $12$ | $X$ | $Y$ |
ને મધ્યસ્થથી સરેરાશ વિચલન $1.25$ હોય, તો $4 x+5 y=$ .............