MCQ
Current in the circuit will be
- A$\frac{5}{{40}}A$
- ✓$\frac{5}{{50}}A$
- C$\frac{5}{{10}}A$
- D$\frac{5}{{20}}A$
✓
Answer
Correct option: B.
$\frac{5}{{50}}A$
b
(b)The diode in lower branch is forward biased and diode in upper branch is reverse biased
$i = \frac{5}{{20 + 30}} = \frac{5}{{50}}A$.
(b)The diode in lower branch is forward biased and diode in upper branch is reverse biased
$i = \frac{5}{{20 + 30}} = \frac{5}{{50}}A$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
At a particular instant the current in the circuit given below is $i$. The displacement current between the plates of the capacitor shown below is ..........
→A FM Broad cast transmitter, using modulating signal of frequency $20\,kHz$ has a deviation ratio of $10$. The Bandwidth required for transmission is $.......kHz$
→Consider the combination of resistors as shown in figure and pick out the correct statement
Which of the following is true
Mark out the correct options.
The figure shows a conducting loop $ABCDA$ placed in a uniform magnetic field perpendicular to its plane. The part $ABC$ is the $(3/4)^{th}$ portion of the square of side length $l$ . The part $ADC$ is a circular arc of radius $R$ . The points $A$ and $C$ are connected to a battery which supply a current $I$ to the circuit. The magnetic force on the loop due to the field $B$ is
→In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength . If wavelength of red light is $6600\,\mathop A\limits^o$ , then wavelength of first maximum will be.....$\mathop A\limits^o $
→A virtual image larger than the object can be obtained by
Which of the following defines electromagnetic induction:
To increase the magnifying power of telescope ($f_o$ = focal length of the objective and $f_e$ = focal length of the eye lens)
→