MCQ
Cyclopentene on treatment with alkaline $KMn{O_4}$ gives
- ACyclopentanol
- Btrans $1, 2-$cyclopentanediol
- ✓cis $1, 2-$cyclopentanediol
- D$1 : 1$ mixture of cis and trans $1, 2-$cyclopentanediol

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Statement $I$ : Bromination of phenol in solvent with low polarity such as $\mathrm{CHCl}_3$ or $\mathrm{CS}_2$ requires Lewis acid catalyst.
Statement $II$ : The lewis acid catalyst polarises the bromine to generate $\mathrm{Br}^{+}$.
In the light of the above statements, choose the correct answer from the options given below :
