- AAn addition reaction
- BA substitution reaction
- ✓An elimination reaction
- DAn oxidation reaction
$C{H_3}C{H_2}Br + Alc\,.\,KOH \to C{H_2} = C{H_2} + KBr + {H_2}O$
There are two types of elimination reactions.
(a) ${E_1} \to $ Unimolecular elimination
(b) ${E_2} \to $ Bimolecular elimination
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The Gibbs free energy change for the above reaction at $298\, K$ is $x \times 10^{-1} \,k\,J\, mol ^{-1}$;
The value of $x$ is ..... [nearest integer]$\left [\text { Given : } E _{ Cu ^{2} / / Cu }=0.34\, V ; E _{ Sn ^{2} / Sn }^{\ominus}=-0.14 \,V ; F=96500\, C\, mol ^{-1}\right]$
$\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-Cl-N{{H}_{3}} \\
\end{matrix}$ $\to $ Inter mediate $\to $ product
