MCQ
$P_4O_{10}$ reacts with $HNO_3$ to give
- A$N_2O, H_3PO_2$
- B$N_2O_3, H_3PO_4$
- C$NO_2, HPO_3$
- ✓$N_2O_5, HPO_3$
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$(i)$ $PtCl _{4} . 5 NH _{3}$ $(ii)$ $PtCl _{4} . 4 NH _{3}$ $(iii)$ $PtCl _{4} . 3 NH _{3}$ $(iv)$ $PtCl _{4}. 2 NH _{3}$
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