Question
Determine the empirical formula of the compound whose composition by mass is $42\%$ nitrogen$, 48\%$ oxygen and $9\%$ hydrogen.$\ [N=14,O=16,H=1]$
| Element | Atomic mass | Percentage | Relative number of moles | Simplest mole ratio | Whole number ratio |
| $N$ | $14$ | $42$ | $42/14 = 3$ | $3/3 = 1$ | $1$ |
| $O$ | $16$ | $48$ | $48/16 = 3$ | $3/3 = 1$ | $1$ |
| $H$ | $1$ | $9$ | $9/1 = 9$ | $9/3 = 3$ | $3$ |
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