Question
Determine the empirical formula of the compound whose composition by mass is $42\%$ nitrogen$, 48\%$ oxygen and $9\%$ hydrogen.$\ [N=14,O=16,H=1]$

Answer

Element Atomic mass Percentage Relative number of moles  Simplest mole ratio Whole number ratio
$N$ $14$ $42$ $42/14 = 3$ $3/3 = 1$ $1$
$O$ $16$ $48$ $48/16 = 3$ $3/3 = 1$ $1$
$H$ $1$ $9$ $9/1 = 9$ $9/3 = 3$ $3$
So the empirical formula of the compound is $NH_2OH.$

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