$(\mathrm{F}-\mathrm{f}) \mathrm{R}=\mathrm{I} \alpha$
$\Rightarrow \mathrm{F}-\mathrm{f}=\frac{\mathrm{I} \alpha}{\mathrm{R}^{2}} \quad(\mathrm{a}=\mathrm{R} \alpha)$
adding
$F=\left(m+\frac{I}{R^{2}}\right) \frac{a}{2}$
$v=0+a t$
$=\frac{2 \mathrm{F}}{\left(\mathrm{m}+\frac{\mathrm{I}}{\mathrm{R}^{2}}\right)} \mathrm{t}$
$\mathrm{K.E.}=\frac{1}{2} \mathrm{mv}^{2}+\frac{1}{2} \mathrm{I} \omega^{2}$
$=\frac{1}{2} \mathrm{V}^{2}\left(\mathrm{m}+\frac{\mathrm{I}}{\mathrm{R}^{2}}\right), \omega=\frac{\mathrm{V}}{\mathrm{R}}$
$=\frac{1}{2}\left(\frac{2 \mathrm{Ft}}{\mathrm{m}+\frac{\mathrm{I}}{\mathrm{R}^{2}}}\right)^{2}\left(\mathrm{m}+\frac{\mathrm{I}}{\mathrm{R}^{2}}\right)=\frac{2 \mathrm{F}^{2} \mathrm{t}^{2}}{\left(\mathrm{m}+\frac{\mathrm{I}}{\mathrm{R}^{2}}\right)}$
$\mathrm{Also}, \mathrm{I}_{\mathrm{B}}>\mathrm{I}_{\mathrm{A}}$ 
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