Question
Discuss graphical method for the measurement of impulse in the following case:
- When constant force acts on the body.
- When a variable force acts on the body.
✓
Answer
$F_1$ for curve (a) is greater than $F_2$ for curve (b). The time $t_2$ for which $F_2$ acts is greater for curve (b) than time $t_1$ in case of curve (a).
$F_1 \times t_1=F_2 \times t_2$
Impulse of variable force
$=\int\limits^{\text{t}_2}_{\text{t}_1}\vec{\text{F}}\text{dt}=\text{aera of }\Delta\text{BCA}$
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