Question
Distinguish between a sigma and a pi bond.
| Sr. No. | Pi bond | Sigma bond |
| 1 | Pi bond is formed by lateral overlapping of orbitals. | Sigma bond is formed by end to end overlapping of orbitals. |
| 2 | It is comparatively weak bond. | It is comparatively strong bond. |
| 3 | There is only one overlapping orbital is p-p. | The overlapping orbitals are s-s, s-p, p-p. |
| 4 | Rotation around pi- bond is restricted. | Rotation is possible around sigma bond. |
| 5 | Electron cloud is not symmetrical about the line joining 2 nuclei. | Electron cloud is symmetrical about the line joining 2 nuclei. |
| 6 | It is having 2 electron clouds one above the plane of atomic nuclei and one below the plane of atomic nuclei. | It is having 1 electron cloud and that is symmetrical about the inter-nuclear axis. |
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$\text{CCI}_4(\text{g})\xrightarrow{ \ \ \ \ \ }\text{C}(\text{g})+4\text{CI}(\text{g})$
and calculate bond enthalpy of C – Cl in CCl4(g).$\Delta_\text{vap}\text{H}^\ominus(\text{CCI}_4)=30.5\text{kJ} \ \text{mol}^{-1}.$
$\Delta_\text{f}\text{H}^\ominus(\text{CCI}_4)=-135.5\text{kJ} \ \text{mol}^{-1}.$
$\Delta_\text{a}\text{H}^\ominus(\text{C})=-715.0\text{kJ} \ \text{mol}^{-1},$ where $\Delta_\text{a}\text{H}^\ominus$ is enthalpy of atomisation
$\Delta_\text{a}\text{H}^\ominus(\text{CI}_2)=242\text{kJ} \ \text{mol}^{-1}$
N2H4(l) + ClO3-(aq) → NO(g) + Cl-(g)