Question
Draw a parallelogram $ABCD$ in which $AB = 6.5\ cm, AD = 4.8\ cm$ and $\angle\text{BAD}=70^{\circ.}$ Measure its diagonals.
✓
Answer
Since $ABCD$ is a parallelogram, $AB = DC = 6.5cm$ and $AD = BC = 4.8cm.$
Given:$\angle\text{A}=70^{\circ}$
Steps of construction:
$1.$Draw $AD$ equal to $4.8\ cm.$
$2.$Make an angle of $70^\circ $ at $A$ and cut an arc of $6.5\ cm$. Name it $B.$
$3.$Cut an arc of $4.8\ cm$ from $B$ and $6.5\ cm$ from $D$. Name it $C.$
$4.$Join $AB, BC$ and $CD.$
$5.$Measuring the diagonal $AC$ and $BD$, we get $AC$ equal to $9.2\ cm$ and $BD$ equal to $6.6\ cm.$
Given:$\angle\text{A}=70^{\circ}$
Steps of construction:
$1.$Draw $AD$ equal to $4.8\ cm.$
$2.$Make an angle of $70^\circ $ at $A$ and cut an arc of $6.5\ cm$. Name it $B.$
$3.$Cut an arc of $4.8\ cm$ from $B$ and $6.5\ cm$ from $D$. Name it $C.$
$4.$Join $AB, BC$ and $CD.$
$5.$Measuring the diagonal $AC$ and $BD$, we get $AC$ equal to $9.2\ cm$ and $BD$ equal to $6.6\ cm.$
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