Draw a parallelogram ABCD, with AB = 6 cm, AD = 4.8 cm and DAB = … - Vidyadip

Question

Draw a parallelogram $\text{ABCD}$, with $AB = 6 \ cm, AD = 4.8 \ cm$ and $\angle DAB = 45^\circ$ . Draw the perpendicular bisector of side $AD$ and let it meet $AD$ at point $P$. Also, draw the diagonals $AC$ and $BD\ ;$ and let them intersect at point $O$. Join $O$ and $P$. Measure $OP$.

✓

Answer

Steps :

Draw $AB = 6 \ cm.$
Draw $\angle PAB = 45^\circ .$
Cut $AD = 4.8 \ cm.$
From $D$, draw an arc of radius $6 \ cm$.
From $B$, draw an arc of radius $4.8 \ cm$ which meets the first arc at $C.$
Join $BC, CD, AD.$
Thus $\text{ABCD}$ is the required $||\ gm.$
Draw perpendicular bisector $XY$ of $AD$ which cuts $AD$ at $P$.
Join $AC$ and $BD$ which intersect at $O$.
Join $OP$ and measure it.$OP = 3 \ cm.$

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