MCQ
Each capacitor in the circuit shown is a $1F$ capacitor. What would be the equivalent capacitance between $A$ and $B?$
- A$0.5F$
- ✓$F$
- C$2F$
- D$4F$
✓
Answer
Correct option: B.
$F$
Equivalent capacitance of each pair of capacitance in series$=\frac{1\times1}{1+1}\text{F}=0.5\text{F}$
The two series combination are connected in parallel. Hence the net capacitance becomes $0.5F + 0.5F = 1F$
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