MCQ
Electricity required for liberating $710\, g$ of $Cl_2(g)$ by electrolyzing a concentrated solution of $NaCl$ will be
- A$1.93 \times {10^5}\,C$
- ✓$1.93 \times {10^6}\,C$
- C$9.65 \times {10^6}\,C$
- D$9.65 \times {10^5}\,C$
$710=\frac{35.5}{96500} \times \mathrm{Q}$
$\mathrm{Q}=1930000=1.93 \times 10^{6}\,\mathrm{C}$
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$4NH_3 + 5O_2 \to 4NO + 6H_2O$
$\Delta S_A^o = 100\frac{J}{{mol \times k}}$ $\Delta S_C^o = 200\frac{J}{{mol \times k}}$
$\Delta S_B^o = 120\frac{J}{{mol \times k}}$ $\Delta S_D^o = 150\frac{J}{{mol \times k}}$
$2{H_2}{O_2}(l) \rightleftharpoons {H_2}O(l) + {O_2}(g)$
$(R = 83\, JK^{-1}\, mol^{-1})$