MCQ
Electronic configuration of chalcons in their outermost orbit is
- A${s^2}{p^3}$
- ✓${s^2}{p^4}$
- C${s^2}{p^5}$
- D${s^2}{p^6}$
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Product of the above reaction is
$(I)\, SP_4 \,\,\,(II)\, XeO_4 \,\,\,(Ill) \,XeF_4 \,\,\,(IV)\, ICl^-_4$
$\mathrm{CH}_{4}+\mathrm{I}_{2} \underset{\text { Reversible }}{\stackrel{\mathrm{hv}}{\longrightarrow}} \mathrm{CH}_{3}-\mathrm{I}+\mathrm{HI}$

| List-I (Complexes) | List-II (Types) |
| (a) $\left[ Co \left( NH _3\right)_5 CN \right] Cl _2$ | (i) ionisation isomerism |
| (b) $\left[ Cr \left( NH _3\right)_6\right]\left[ Co ( CN )_6\right]$ | (ii) coordination isomerism |
| (c) $\left[ Co \left( NH _3\right)_5\left( SO _4\right)\right] Br$ | (iii) linkage isomerism |