MCQ
Electronic configuration of sodium is :
- A$(2, 8, 1)$
- B$(2, 8, 2)$
- C$(2, 8, 3 )$
- ✓$(2, 8, 4)$
✓
Answer
Correct option: D.
$(2, 8, 4)$
Atomic no. of $\ce{Na}$ is $11$ thus the $\ce{E.C}$ is : $2, 8, 1$
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