MCQ
$EN$ of element $A$ is $E_1$ and $IP$ is $E_2$ hence $EA$ will be
- ✓$2E_1 -E_2$
- B$E_1 -E_2$
- C$E_1 -2E_2$
- D$(E_1 + E_2)/2$
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$(I)\, [CrCl_2(NO_2)_2(NH_3)_2]^-$ $(II)\, [Co(NO_2)_3(NH_3)_3]$
$(III)\, [PtCl(NO_2)(NH_3 )(py)]$ $(IV)\, [PtBrCl(en)]$
$(I)\,\,\,-\,\,\,(II)\,\,\,-\,\,\,(III)\,\,\,-\,\,\,(IV)$
(Given : $K_b$ of water $=0.5\ Kkg/mol$ . ; Atomic mass of $Ca =40$ , $Br =80$)