MCQ
Ethyl nitrite on reduction with Sn/ HCI gives:
  • A
    C2​H5​NH​+ HNO2
  • B
    C2​H5​NH2​ + H2​O
  • C
    C2​H5​OH + NH4​OH
  • D
    C2​H5​OH + NaNO2

Answer

  1. C2​H5​OH + NH4​OH

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  {O\,\,\,\,\,\,} \\ 
  {||\,\,\,\,\,\,} \\ 
  {H - C - CC{l_3}} 
\end{array}$ $\xrightarrow{{{H_2}S{O_4}}}$ 

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  {C{H_3} - C = C{H_2}} \\ 
  |\,\,\, \\ 
  \,\,\,{C{H_3}} 
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