MCQ
The IUPAC name for tertiary butyl iodide is:
- A4-iodobutane
- B2-iodobutane
- C1-iodo-3-methylpropane
- D2-iodo-2-methylpropane
✓
Answer
- 2-iodo-2-methylpropane
Explanation:
There are certain steps that we follow during IUPAC nomenclature such as:
Step 1: Find and name the longest continuous carbon chain.
Step 2: Identify and name groups attached to this chain.
Step 3: Do the numbering.
Step 4: Designate the location of each substituent group by an appropriate number and name.
Step 5: Assemble the name, listing groups in alphabetical order using the full name.
So, here in this case the longest continuous chain is of 3 C so the base name would be propane.
There is a methyl group and Iodine group present at C−2 position so the substituent naming would be according to alphabetical order as; 2−Iodo−2−Methyl.
Therefore, The IUPAC name of a compound is 2−iodo−2−methylpropane.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Bayer’s reagent used to detect olifinic double bond is
The difference in electronegativity of carbon-halogen bond is minimum in:
Azo dye is prepared by the coupling of phenol and :
In a pseudo first order hydrolysis of ester in water, the following results were obtained
→| $t/s$ | $0$ | $30$ | $60$ | $90$ |
| $ Ester/$ $mol\,L^{-1}$ | $0.55$ | $0.31$ | $0.17$ | $0.085$ |
What will be the average rate of reaction between the time interval $30$ to $60\, seconds$ ?
Which of the following reagents can distinguish between propanal and propanone ?
Elevation in boiling point was ${0.52\,^o}C$ when $6\,gm$ of a compound $X$ was dissolved in $100\,gm$ of water. Molecular weight of $X$ is $({K_b}$ for water is $0.52$ per $1000\,gm$ of water)
→The catalyst used in the contact process is
When carboxylic acid reacts with organolithium reagents to give ketones side reaction sometimes occur. For example,
→$\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
HOC{{H}_{2}}C{{H}_{2}}CHC{{H}_{2}}C{{H}_{2}}COH \\
\end{matrix}$ $\xrightarrow[tetrahydro\,\,futan ]{(x)\,\,C{{H}_{3}}Li}$ $\xrightarrow[{{H}_{2}}]{N{{H}_{4}}Cl}$ $\underset{Compound\,\,\,A\,\,63\,\%}{\mathop{\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\, \\
\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
HOC{{H}_{2}}C{{H}_{2}}CHC{{H}_{2}}C{{H}_{2}}-C-C{{H}_{3}} \\
\end{matrix}}}\,$ $\underset{37\,\%}{\mathop{+\,\,Compound\,\,(B)}}\,$
Value of $(x)$ in above reaction is
$SO_2$ can reduce
→Carbyl-amine reaction is given by