MCQ
Ethylene oxide when treated with Grignard reagent yields
- ✓primary alcohol
- Bsecondary alcohol
- Ctertiary alcohol
- Dcyclopropyl alcohol.

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$\ln {k_t} = \ln {k_0} + \left( {\frac{{\ln \left( {\frac{5}{2}} \right)}}{{10}}} \right) \times t\left( {t \geqslant 0{}\,^0C} \right)$
$K_0$ =rate constant at $0\,^o C$ ; $k_t$ = rate constant at $t\,^o C$
Temperature coefficient of reaction, assuming that the rate constant increases same number of times on each $10\,^oC$ rise in temperature, is
$2NO(g) + 2{H_2}(g) \to {N_2}(g) + 2{H_2}O(g)$ is :
Step $1$ : $2NO(g) + {H_2}(g)\xrightarrow{{slow}}{N_2} + {H_2}{O_2}$
Step : $2$ ${H_2}{O_2} + {H_2}\xrightarrow{{fast}}2{H_2}O$
Then the correct statement is
