MCQ
Ethylene reacts with sulphur monochloride to form
- AEthyl chloride
- BEthylene chloride
- ✓Mustard gas
- DEthylidene chloride
✓
Answer
Correct option: C.
Mustard gas
c
$2\begin{array}{*{20}{c}}
{C{H_2}} \\
{||\,\,\,\,\,} \\
{C{H_2}}
\end{array} + {S_2}C{l_2} \to $ $\mathop {\begin{array}{*{20}{c}}
{C{H_2} - Cl\,\,\,C{H_2} - Cl\,\,\,\,} \\
{\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - S - C{H_{2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}}
\end{array}}\limits_{MUSTARD\,GAS} + S$
$2\begin{array}{*{20}{c}}
{C{H_2}} \\
{||\,\,\,\,\,} \\
{C{H_2}}
\end{array} + {S_2}C{l_2} \to $ $\mathop {\begin{array}{*{20}{c}}
{C{H_2} - Cl\,\,\,C{H_2} - Cl\,\,\,\,} \\
{\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - S - C{H_{2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}}
\end{array}}\limits_{MUSTARD\,GAS} + S$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Quantum numbers of an atom can be defined on the basis of
The heat of combustion of carbon to $CO_2$ is $ -393.5\ kJ/mol.$ The heat released upon formation of $35.2\ g$ of $CO_2$ from carbon and oxygen gas is
→If doubling the initial concentration of reactant doubles $t_{1/2}$ of reaction, the order of reaction is
→Which bond angle $\theta $ would result in the maximum dipole moment for the triatomic molecule $YXY$
→Which compound is not a monobasic acid ?
$C{u^{2 + }}(aq.) + {X^ - }(aq.)\xrightarrow{{R.T.}}CuX \downarrow + {X_2}$
→$'X'$ cannot be
Number of acidic hydrogen atoms in butyne$-1$ are
→Find the emf of the cell in which the following reaction takes place at $298 \,K$ (In $V$)
→$Ni ( s )+2 Ag ^{+}(0.001 M ) \rightarrow Ni ^{2+}(0.001 M )+2 Ag ( s )$
$($ Given that $E _{\text {cell }}^{\circ}=10.5 \,V , \frac{2.303 RT }{ F }=0.059$ at $298\, K )$
$KI$ when heated with conc. ${H_2}S{O_4}$ gives
→$(A)$ will be
→