Question
Evaluate: $\Big(\frac{-2}{3}\Big)^{-5}$
✓
Answer
$\Big(\frac{-2}{3}\Big)^{-5}$ $=\Big(\frac{3}{-2}\Big)^{5}$ $=\frac{3^{5}}{-2^{5}}$ $=\frac{243}{-32}$ $=\frac{243\times-1}{-32\times-1}$ $=\frac{-243}{32}$
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