Evaluate: x^2-2 x d x - Vidyadip

Question

Evaluate: $\int \sqrt{x^2-2 x} d x$

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Answer

$I=\int \sqrt{(x-1)^2-1^2 d x}$
$=\frac{(x-1)}{2} \sqrt{x^2-2 x}-\frac{1}{2} \log \left|x-1+\sqrt{x^2-2 x}\right|+C$

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