Question
Explain how the scattering experiment can be analyzed in detail from Rutherford's nuclear model.

Answer

Image

The figure shows a graph of the number of $\alpha$-particles scatterd versus the angle of scattering.
The scattering experiment can be analysed in detail from Rutherford's nuclear model. Since the gold foil is very thin, it can be assumed that $\alpha$-particles will suffer not more than one scattering during their passage through it. Hence it is sufficient to calculate the path (trajectory) of an $\alpha$-particle scattered by a single nucleus.
$\alpha$-particles are nuclei of helium atoms, so they have two units mass of positive charge $2 e$ and mass equal to that of a helium atom. The charge of the gold nucleus is Ze , where Z is the atomic number of the atom; for gold $Z =79$.
Since the nucleus of gold is about 50 times heavier than an $\alpha$-particle, it remains stationary throughout the scattering process.
The trajectory of an $\alpha$-particle can be calculated using newton's second law of motion and the coulomb's law for electrostatic force of repulsion between the $\alpha$-particle and the positively charged nucleus.
The magnitude of this force is
$F =\frac{1}{4 \pi \varepsilon_0} \frac{(2 e)( Ze )}{r^2}$
Where, $r$ is the distance between the $\alpha$-particle and the nucleus.
The force is directed along the line joining the $\alpha$-particle and the nucleus.
The magnitude and direction of the force on an $\alpha$-particle changes continuously as it moves towards and away from the nucleus.

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