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PART - 1 CH - 4 Carbon and Its Compounds — Science STD 10 — Question

Gujarat BoardEnglish MediumSTD 10SciencePART - 1 CH - 4 Carbon and Its Compounds4 Marks
Question
Explain the formation of covalent bonds in oxygen molecule $(\text O _2$).
✓

Answer

The atomic number of oxygen is 8, so its electronic configuration is $\begin{array}{ll}
\text K &\text L \\
2 & 6
\end{array} .$
$\rightarrow$ Thus, oxygen has six electrons in its $\text L$ shell.
$\rightarrow$ Therefore, it needs two more electrons to fill the $\text L$ shell.
$\rightarrow$ Hence, two atoms of oxygen share two electrons of $\text L$ shell to form a molecule of oxygen $(\text O_2)$.
$\rightarrow$ As a result, each atom of oxygen attains the electronic configuration of their nearest noble gas neon (Ne), which has eight electrons in their $\text L$ shell.
$\rightarrow$ These four valence electrons are depicted by dots or crosses is shown as follows :
Image

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