Question
Factorise: $\left(6 \frac{2}{3}\right)^2-\left(2 \frac{1}{3}\right)^2$

Answer

$ \left(6 \frac{2}{3}\right)^2-\left(2 \frac{1}{3}\right)^2$
$ =\left(\frac{20}{3}\right)^2-\left(\frac{7}{3}\right)^2$
$ =\left(\frac{20}{3}+\frac{7}{3}\right)\left(\frac{20}{3}-\frac{7}{3}\right)$
$ =\left(\frac{27}{3}\right)\left(\frac{13}{3}\right)=9 \times \frac{13}{3}=39$

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